How do you find the domain of inverse trig functions?

Question

How do you find the domain of inverse trig functions?

1 Answer

Impact of this question

8092 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-24T08:21:22

The domain of any inverse trig function ( $arcsin$ $arcsin$ , $arccos$ $arccos$ , $arctan$ $arctan$ ) is equal to the range of the corresponding trig function ( $sin$ $sin$ , $cos$ $cos$ , $tan$ $tan$ ).

So the domain of $arcsin$ $arcsin$ and $arccos$ $arccos$ is ${x in RR : -1 <= x <= 1}$ since $-1 <= sin theta <= 1$ and $-1 <= cos theta <= 1$ for all $theta in RR$ .

The domain of $arctan$ is $RR$ since the range of $tan theta$ is the whole of $RR$ .

The domain of $sec^-1$ and $csc^-1$ is ${x in RR : x <= -1 or x >= 1}$

The domain of $cot^-1$ is $RR$ .

Science

Math

Humanities

... and beyond

How do you find the domain of inverse trig functions?

1 Answer

Related questions

Impact of this question