How do you find the equation for the parabola with the vertex (1,4) that passes through the point (3,8)?

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Answer 1 · 2018-06-12T06:16:19

#y=(x-1)^2+4#

Given -

Vertex #(1, 4)#
Point #(3, 8)#

The formula is

#y=a(x-h)^2+k#

Where -

#h=1#
#k=4#

Then-

#y=a(x-1)^2+4#

Find the value of #a# when one of the points is #(3, 8)#

#8=a(3-1)^2+4#
#8=4a+4#
#4a+4=8#
#4a=8-4=4#
#4a=4#
#a=4/4=1#
#a=1#

#y=1(x-1)^2+4#

#y=(x-1)^2+4#

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