Question

How do you find the equation of a circle in standard form given C(-2,8) and r=4?

Answer 1

The equation of circle is `(x+2)^2 +(y-8)^2=16`

Explanation:

The equation of circle in standard form is `(x-h^2) + (y-k)^2 =r^2` , where `(h,k)` is co-ordinate of centre and `r` is the radius of circle.

So The equation of circle is `(x - (-2))^2 + (y-8)^2 =4^2 or (x+2)^2 +(y-8)^2=16` [Ans]