How do you find the equation of a line passing through (4, 1) with the slope m = -1/2?

2 Answers
Apr 29, 2018

See below:

Explanation:

Point (x_1, y_1)=(4, 1)

Slope (m) =-1/2

Let the equation of the line be

y-y_1=m(x-x_1)

y-1=-1/2(x-4)

y-1=-1/2x+2

x/2+y=3

which is the required equation of the line.

Apr 29, 2018

y=-1/2x+3

Explanation:

Slope-intercept form of a line: y=mx+b, with m as the slope and b as the y-intercept

We know that the slope is -1/2, so we can put that in for m:

y=-1/2x+b rarr To find the y-intercept, plug in the point (4, 1) and solve

1=-1/2*4+b

1=-2+b

b=3

The equation in slope-intercept form is y=-1/2x+3