# How do you find the exact value for csc(sin^-1 (sqrt 3/2))?

$\csc \left({\sin}^{-} 1 \left(\frac{\sqrt{3}}{2}\right)\right) = \frac{2}{\sqrt{3}} = \frac{2 \sqrt{3}}{3}$
because ${\sin}^{-} 1 \left(\frac{\sqrt{3}}{2}\right) = \frac{\pi}{3}$ ,the angle$= {60}^{\circ}$
therefore $\csc \left(\frac{\pi}{3}\right) = \csc \left({60}^{\circ}\right) = \frac{2}{\sqrt{3}} = \frac{2 \sqrt{3}}{3}$