# How do you find the exact value of arc sin (sqrt3/2)?

If $\theta = \arcsin \left(\frac{\sqrt{3}}{2}\right)$
$\sin \left(\theta\right) = \frac{\sqrt{3}}{2}$
with $\theta = {60}^{o} = \frac{\pi}{3} \text{radians}$ (if we restrict ourselves to the first quadrant)