Question

How do you find the exact value of `cos^-1(sqrt3/2)`?

Answer 1

The angle is `30º` or `pi/6+2pin`
or `-30º` or`-pi/6+2pin`

Explanation:

Let `theta=cos^(-1)(sqrt3/2)`

So `costheta=sqrt3/2`
`cos` is `>=0` in the 1st and 4th quadrant

So `theta=30º (pi/6 rad)`
and `theta =-30º (-pi/6 rad)`