How do you find the exact value of sin(arcsin (1/6))?

Jun 7, 2016

$\frac{1}{6}$

Explanation:

arcsinx $= {\sin}^{-} 1 x \text{ the inverse sin of x}$

What this tells us is that ${\sin}^{-} 1 x \text{ is the inverse function of sinx}$

The inverse function 'undoes' what the function does.

$\Rightarrow \sin \left({\sin}^{-} 1 \left(\frac{1}{6}\right)\right) = \frac{1}{6}$