# How do you find the exact value of tan^-1 (sqrt3/3)?

${30}^{\circ}$
$\frac{\sqrt{3}}{3} = \frac{1}{\sqrt{3}}$
$\tan 30 = \sin \frac{30}{\cos} 30 = \frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}} = \frac{1}{\sqrt{3}}$
${\tan}^{- 1} \left(\frac{1}{\sqrt{3}}\right) = {30}^{\circ}$