# How do you find the exact value of tan(tan^-1 25)?

${25}^{o}$
Let say $\theta = \tan \left({\tan}^{-} 1 25\right)$
${\tan}^{-} 1 \left(\theta\right) = {\tan}^{-} 1 \left(25\right)$
$\theta = 25$