# How do you find the exact values of arctan sqrt3?

$\frac{\pi}{6} \mathmr{and} \frac{7 \pi}{6}$
$\tan x = \sqrt{3}$ --> arc $x = \frac{\pi}{6}$ , or $x = {30}^{\circ}$
$x = \frac{\pi}{6} + \pi = \frac{7 \pi}{6}$