# How do you find the GCF of 25x^3, 45x^4, 65x^2?

$2925 {x}^{4}$

#### Explanation:

Find the factors of each first.
$25 {x}^{3} = {5}^{2} \cdot {x}^{3}$
$45 {x}^{4} = {3}^{2} \cdot 5 \cdot {x}^{4}$
$65 {x}^{2} = 5 \cdot 13 \cdot {x}^{2}$

Use this to find the prime factorization of the GCF.
${3}^{2} \cdot {5}^{2} \cdot 13 \cdot {x}^{4}$

Solve.
${3}^{2} \cdot {5}^{2} \cdot 13 \cdot {x}^{4} = 2925 {x}^{4}$