How do you find the general anti-derivative of #f(x) = 1/2 + (3/4)x^2 - (4/5)x^3#?

1 Answer
bp
Apr 12, 2015

#x/2# +#x^3/4# -#x^4 /5# +C

General anti-derivative can be derived by using applying power rule for integrating f(x) term by term. According to this rule, anti-derivative of #x^n# is #x^n /(n+1)#, where x#!= -1#

= #x/2# + #3/4# #x^3 /3# - #4/5 x^4/4# +C

= #x/2# + #x^3 /4# - #x^4 /5# +C

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