# How do you find the indefinite integral of int (-2x^-3) dx?

Dec 7, 2016

${x}^{- 2} + c$

#### Explanation:

Given -

$\int \left(- 2 {x}^{- 3}\right) \mathrm{dx}$

$- 2 \int x \left(- 3\right) \mathrm{dx}$

$- 2 \cdot \frac{{x}^{- 3 + 1}}{- 3 + 1} + c$

$- 2 \cdot \frac{{x}^{- 2}}{- 2} + c$
$\cancel{- 2} \cdot \frac{{x}^{- 2}}{\cancel{- 2}} + c$

${x}^{- 2} + c$

Where $c$ is a constant