How do you find the indefinite integral of #int (-2x^-3) dx#?
1 Answer
Dec 7, 2016
#x^(-2)+c#
Explanation:
Given -
#int(-2x^(-3))dx#
#-2intx(-3)dx#
#-2*(x^(-3+1))/(-3+1)+c#
#-2*(x^(-2))/(-2)+c#
#cancel(-2)*(x^(-2))/cancel(-2)+c#
#x^(-2)+c#
Where
