How do you find the indefinite integral of #int (4sinx)/(3tanx)dx#?

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Answer 1 · 2016-12-07T10:13:20

The answer is #=4/3sinx+C#

We use #tanx=sinx/cosx#

#(4sinx)/(3tanx)#

#=(4sinx)/(3sinx/cosx)#

#=4/3cosx#

So,

#int(4tanxdx)/(3cosx)=4/3intcosxdx#

#=4/3sinx+C#