# How do you find the indefinite integral of int -6x dx?

$\int - 6 x \mathrm{dx} = - 3 {x}^{2} + c$
$\int - 6 x \mathrm{dx} = - \frac{6 {x}^{2}}{2} + c = - 3 {x}^{2} + c$
$\int {x}^{n} \mathrm{dx} = {x}^{n + 1} / \left(n + 1\right)$