How do you find the indefinite integral of #int (7u^(3/2)+2u^(1/2))du#?
1 Answer
Oct 7, 2016
Explanation:
We can integrate each term using the
#color(blue)"power rule"# That is
#color(red)(bar(ul(|color(white)(a/a)color(black)(int(ax^n)dx=a/(n+1)x^(n+1))color(white)(a/a)|)))#
#rArrint(7u^(3/2)+2u^(1/2))du#
#=7/(5/2)u^(3/2+1)+2/(3/2)u^(1/2+1)+c#
#=14/5u^(5/2)+4/3u^(3/2)+c# where c is the constant of integration.
