Question

How do you find the indefinite integral of `t^(9/2)+8t^(1/2)-8t^(-1/2)dt`?

Answer 1

You can separate it into three integrals and take out `8` from the integral sign:
`intt^(9/2)dt+8intt^(1/2)dt-8intt^(-1/2)dt=`

and use the fact that:
`intt^ndt=t^(n+1)/(n+1)+c`
where `n` is the exponent of `t`