How do you find the intercept and vertex of #y = x^2 -12#?
The graph of y=x^2 -12 would be a parabola please go through the explanation to understand the approach to work similar problems.
Let us understand the vertex form of such parabola.
If the parabola is of form
Let us compare our equation with this form.
Let us rewrite this as
Comparing we can see
Intercepts are the places where the curve cuts the axis. The y intercept is found by equating x=0 and solving for y and the x intercept are found by equating y =0 and solving for x.
In our problem the vertex is the y-intercept as well.
To find x-intercepts equate y=0 and solve.
The x-intercepts are