How do you find the inverse of sin?

1 Answer
Apr 15, 2015

The inverse of the #sin# function is the #arcsin# function.
But sine itself, would not be invertible because it's not injective, so it's not bijective (invertible).
To obtain arcsine function we have to restrict the domain of sine to #[-pi/2,pi/2]#.

#arcsin(sin(theta)) = theta " if and only if"-pi/2<=theta<=pi/2#

For example:
Since #sin(pi/6) = 1/2#
#arcsin(1/2) = pi/6#

If you meant by your question "how do you calculate the value of the #arcsin# for some given number?"
then the answer is that there is no easy way to do this (with the exception of a few special values) just as there is no easy way to calculate the value of #sin# for most values.