# What are the components of the vector between the origin an the polar coordinate (6, pi/12)?

$x = r \cos \theta = 6 \cdot \cos \left(\frac{\pi}{12}\right) = 5.7956$
$y = r \sin \theta = 6 \sin \left(\frac{\pi}{12}\right) = 1.5529$
$\tan \theta = \tan \left(\frac{\pi}{12}\right) = \frac{y}{x} = 0.2679$