# How do you find the max or minimum of f(x)=3x^2?

Dec 27, 2016

Differentiate the function and equate the differential to 0, then solve for x.

#### Explanation:

$\frac{\mathrm{dy}}{\mathrm{dx}} 3 {x}^{2} = 6 x$

Let $6 x = 0$

$x = \frac{0}{6} = 0$

The critical point (max or min) is at $x = 0$. To find the y coordinate of this point substitute $x = 0$ into the original equation. $y = 3 {\left(0\right)}^{2} = 0$
Thus the coordinates of the min/max point are $0 , 0$.