Question

How do you find the maximum mass of aluminium that can react with 0.5 moles of HCI? 2Al + 6HCI - > 2Al2Cl3 + 3H2

Answer 1

The mass of aluminium will be 4.5 g.

Explanation:

Step 1. Start with the balanced equation.

The balanced equation is

`M_text(r):color(white)(m) 26.98`
`color(white)(mmmll)"2Al" + "6HCl" → "2AlCl"_3 + "3H"_2`

Step 2. Calculate the moles of `"Al"`.

`"Moles of Al" = 0.5 color(red)(cancel(color(black)("mol HCl"))) × ("2 mol Al")/(6 color(red)(cancel(color(black)("mol Al")))) = "0.17 mol Al"`

3. Calculate the mass of `"Al"`.

`"Mass of Al" = 0.17 color(red)(cancel(color(black)("molAl"))) × "26.98 g Al"/(1 color(red)(cancel(color(black)("mol Al")))) = "4.5 g Al"`