# How do you find the maximum mass of aluminium that can react with 0.5 moles of HCI? 2Al + 6HCI - > 2Al2Cl3 + 3H2

May 13, 2017

The mass of aluminium will be 4.5 g.

#### Explanation:

The balanced equation is

${M}_{\textrm{r}} : \textcolor{w h i t e}{m} 26.98$
$\textcolor{w h i t e}{m m m l l} {\text{2Al" + "6HCl" → "2AlCl"_3 + "3H}}_{2}$

Step 2. Calculate the moles of $\text{Al}$.

$\text{Moles of Al" = 0.5 color(red)(cancel(color(black)("mol HCl"))) × ("2 mol Al")/(6 color(red)(cancel(color(black)("mol Al")))) = "0.17 mol Al}$

3. Calculate the mass of $\text{Al}$.

$\text{Mass of Al" = 0.17 color(red)(cancel(color(black)("molAl"))) × "26.98 g Al"/(1 color(red)(cancel(color(black)("mol Al")))) = "4.5 g Al}$