Question

How do you find the maximum or minimum of `f(x)=-x^2-9`?

Answer 1

Maximum of `f(x)=-x^2-9` is `-9`.

Explanation:

As `f(x)=-x^2-9` is always negative, and ir contains the variable term `-x^2`, which can have a maximum value of `0`

the maximum of `f(x)=-x^2-9` is `-9`.

graph{-x^2-9 [-19.34, 20.66, -24.08, -4.08]}