How do you find the period, amplitude and sketch y=-sin((2pix)/3)?

Nov 23, 2017

Amplitude = -1, Period = 3#

Explanation:

Standard form of equation is
$y = a \sin \left(b x + c\right) + d$
Where amplitude = a, Period = $2 \frac{\pi}{b}$
Given equation is

$y = - \sin \left(\frac{2 \pi x}{3}\right)$
graph{-sin(2pi x)/3 [-10, 10, -5, 5]}
Amplitude = a = -1
Period $= \left(2 \frac{\pi}{b}\right) = \left(\frac{2 \pi}{\frac{2 \pi}{3}}\right) = 3$