How do you find the period, phase and vertical shift of y=csc(theta+pi)?

Oct 31, 2017

Amplitude a =1

$P e r i o d = 2 \pi$

Phase shift $= \pi$

Vertical shift $= 0$

Explanation:

$y = a \csc \left(b x + c\right) + d$ is the standard form of equation.
Amplitude a =1

$P e r i o d = \frac{2 \pi}{b} = 2 \pi$

Phase shift $= \frac{c}{b} = \frac{\pi}{1} = \pi$

Vertical shift $= d = 0$