How do you find the product $(3q-5r)^2$ ?

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Answer 1 · 2017-07-19T01:53:33

See a solution process below:

We can use the special case rule:

$(color(red)(a) - color(blue)(b))^2 = color(red)(a)^2 - 2color(red)(a)color(blue)(b) + color(blue)(b)^2$

Substituting $color(red)((3q))$ for $color(red)(a)$ and $color(blue)((5r))$ for $color(blue)(b)$ gives:

$(color(red)(3q) - color(blue)(5r))^2 => color(red)((3q))^2 - (2 * color(red)(3q) * color(blue)(5r)) + color(blue)((5r))^2 =>$

#9q^2 - 30qr + 25r^2

How do you find the product (3q-5r)^2(3q-5r)^2?