How do you find the product #(3q-5r)^2#?

1 Answer
Jul 19, 2017

Answer:

See a solution process below:

Explanation:

We can use the special case rule:

#(color(red)(a) - color(blue)(b))^2 = color(red)(a)^2 - 2color(red)(a)color(blue)(b) + color(blue)(b)^2#

Substituting #color(red)((3q))# for #color(red)(a)# and #color(blue)((5r))# for #color(blue)(b)# gives:

#(color(red)(3q) - color(blue)(5r))^2 => color(red)((3q))^2 - (2 * color(red)(3q) * color(blue)(5r)) + color(blue)((5r))^2 =>#

#9q^2 - 30qr + 25r^2