How do you find the product #(b+8)(b+2)#?

2 Answers
Apr 24, 2017

Answer:

By multiplying, you can get #b^2+10b+16#

Explanation:

Multiply all terms #(b+8)(b+2)#
#b^2+2b+8b+16#
Arrange this as:

#b^2+10b+16#.

This is your answer.

Apr 24, 2017

Answer:

See the entire solution process below:

Explanation:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(b) + color(red)(8))(color(blue)(b) + color(blue)(2))# becomes:

#(color(red)(b) xx color(blue)(b)) + (color(red)(b) xx color(blue)(2)) + (color(red)(8) xx color(blue)(b)) + (color(red)(8) xx color(blue)(2))#

#b^2 + 2b + 8b + 16#

We can now combine like terms:

#b^2 + (2 + 8)b + 16#

#b^2 + 10b + 16#