How do you find the product of #(6v+3)(6v-3)#?

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Answer 1 · 2016-06-29T12:15:14

#(6v+3)(6v-3)=36v^2-9#

We can use the identity #(a+b)(a-b)=a^2-b^2#

Here we have #(6v+3)(6v-3)#

= #(6v)^2-3^2#

= #36v^2-9#

Even if one intends to multiply

#(6v+3)(6v-3)#

= #6v(6v-3)+3(6v-3)#

= #(6v)^2-18v+18v-3^2#

= #36v^2-9#