How do you find the product of #(6x + 7)^2#?

1 Answer
Mar 6, 2018

Answer:

See a solution process below:

Explanation:

This is a special form of the quadratic:

#(color(red)(a) + color(blue)(b))^2 = (color(red)(a) + color(blue)(b))(color(red)(a) + color(blue)(b)) = color(red)(a)^2 + 2color(red)(a)color(blue)(b) + color(blue)(b)^2#

Let:

#a = 6x# and #b = 7#

Substituting gives:

#(color(red)(6x) + color(blue)(7))^2 =>#

#(color(red)(6x) + color(blue)(7))(color(red)(6x) + color(blue)(7)) =>#

#color(red)((6x))^2 + (2 xx color(red)(6x) xx color(blue)(7)) + color(blue)(7)^2 =>#

#36x^2 + 84x + 49#