How do you find the product [(t^2+3t-8)-(t^2-2t+6)](t-4)? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer Anjali G · Sonnhard Jun 6, 2018 [(t^2+3t-8)-(t^2-2t+6)] (t-4) = 5t^2-34t+56 Explanation: [(cancel(t^2)+3t-8)-(cancel(t^2)-2t+6)] (t-4) = (5t-14)(t-4) We have the first term: t^2+3t-8-t^2+2t+6=5t-14 so we get [(cancel(t^2)+3t-8)-(cancel(t^2)-2t+6)] (t-4) = (5t-14)(t-4) (5t-14)(t-4)=5t^2-14t-20t+56 Combining like terms, we get: 5t^2-34t+56 Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply (x-2)(x+3)? How do you simplify (-4xy)(2x^4 yz^3 -y^4 z^9)? How do you multiply (3m+1)(m-4)(m+5)? How do you find the volume of a prism if the width is x, height is 2x-1 and the length if 3x+4? How do you multiply (a^2+2)(3a^2-4)? How do you simplify (x – 8)(x + 5)? How do you simplify (p-1)^2? How do you simplify (3x+2y)^2? See all questions in Multiplication of Polynomials by Binomials Impact of this question 3379 views around the world You can reuse this answer Creative Commons License