# How do you find the radius of a circle with equation #(x-2)^2+(y-2)^2=r^2# that contains the point at (2,5)?

##### 1 Answer

Apr 24, 2018

#### Explanation:

If the **circle** **passes through** the

point

But, in the **given eqn.** of circle, **radius.**

Therefore, the **radius** of the **circle in question** is