How do you find the range and domain of sin(arctan x)sin(arctanx)?

1 Answer
Jun 11, 2017

Range for sin(arctanx)sin(arctanx) is [-1,1][1,1], and domain is (-oo,oo)(,).

Explanation:

arctanxarctanx is always from -pi/2π2 to pi/2π2, but here xx can take any value from (-oo.oo)(.), which is domain for sin(arctanx)sin(arctanx).

But sin(arctanx)sin(arctanx) can take values only from [-1,1][1,1]

Hence range for sin(arctanx)sin(arctanx) is [-1,1][1,1].