How do you find the slope and intercept of #-10x+4y=0#?

2 Answers
Jul 31, 2017

Answer:

#"slope "=5/2," intercept "=0#

Explanation:

#"the equation of a line in "color(blue)"slope-intercept form"# is.

#•color(white)(x)y=mx+b#

#"where m represents the slope and b the y-intercept"#

#"arrange "-10x+4y=0" into this form"#

#"add 10x to both sides"#

#cancel(-10x)cancel(+10x)+4y=0+10x#

#rArr4y=10x+0#

#"divide both sides by 4"#

#(cancel(4) y)/cancel(4)=10/4x+0#

#rArry=5/2x+0larrcolor(red)" in slope-intercept form"#

#rArr"slope "=5/2," y-intercept "=0#
graph{5/2x [-10, 10, -5, 5]}

Jul 31, 2017

Answer:

Slope is #5/2# and y-intercept is #0#

Explanation:

# -10x +4y =0 or 4y =10x or y = 10/4x or y =5/2x #

The slope intercept form of a straight line is #y=mx+c # ,

where #m# is slope and #c# is y-intercept.

Comparing # y= 5/2x+0# with #y=mx+c # we get

Slope as #m=5/2# and y-intercept as # c=0#

graph{-10x+4y=0 [-10, 10, -5, 5]} [Ans]