# How do you find the slope and intercept of -10x+4y=0?

Jul 31, 2017

$\text{slope "=5/2," intercept } = 0$

#### Explanation:

$\text{the equation of a line in "color(blue)"slope-intercept form}$ is.

•color(white)(x)y=mx+b

$\text{where m represents the slope and b the y-intercept}$

$\text{arrange "-10x+4y=0" into this form}$

$\text{add 10x to both sides}$

$\cancel{- 10 x} \cancel{+ 10 x} + 4 y = 0 + 10 x$

$\Rightarrow 4 y = 10 x + 0$

$\text{divide both sides by 4}$

$\frac{\cancel{4} y}{\cancel{4}} = \frac{10}{4} x + 0$

$\Rightarrow y = \frac{5}{2} x + 0 \leftarrow \textcolor{red}{\text{ in slope-intercept form}}$

$\Rightarrow \text{slope "=5/2," y-intercept } = 0$
graph{5/2x [-10, 10, -5, 5]}

Jul 31, 2017

Slope is $\frac{5}{2}$ and y-intercept is $0$

#### Explanation:

$- 10 x + 4 y = 0 \mathmr{and} 4 y = 10 x \mathmr{and} y = \frac{10}{4} x \mathmr{and} y = \frac{5}{2} x$

The slope intercept form of a straight line is $y = m x + c$ ,

where $m$ is slope and $c$ is y-intercept.

Comparing $y = \frac{5}{2} x + 0$ with $y = m x + c$ we get

Slope as $m = \frac{5}{2}$ and y-intercept as $c = 0$

graph{-10x+4y=0 [-10, 10, -5, 5]} [Ans]