How do you find the slope and intercept of #2x = 1/2y + 2#?

1 Answer
Feb 11, 2017

Answer:

#"slope "=4," y-intercept "=-4#

Explanation:

The equation of a line in #color(blue)"slope-intercept form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))#
where m represents the slope and b, the y-intercept.

#"Rearrange " 2x=1/2y+2" into this form"#

#1/2y+2=2xlarr" reversing the equation"#

subtract 2 from both sides.

#1/2ycancel(+2)cancel(-2)=2x-2#

#rArr1/2y=2x-2#

multiply terms on both sides by 2

#y=4x-4larrcolor(red)" in form y=mx+b"#

#rArr"slope "=m=4" and y-intercept "=b=-4#
graph{4x-4 [-10, 10, -5, 5]}