# How do you find the slope and intercept of 4x – 8y = 8?

May 31, 2016

Transforming the equation in $y = m x + q$.

#### Explanation:

When you have the equation in the format

$y = m x + q$ you call $m$ the slope and $q$ the intercept.
So we need to transform the equation in that format.

$4 x - 8 y = 8$

first of all we put the terms with the $y$ on the left and all the other terms on the right, remembering that when we make the "jump" of the $=$ we have to change the sign.

$- 8 y = - 4 x + 8$

Then we want to have only the $y$ on the left, without the $- 8$. To obtain it we divide left and right for $- 8$.

$\setminus \frac{- 8 y}{- 8} = \setminus \frac{- 4 x}{- 8} + \setminus \frac{8}{- 8}$

and doing the calculation, paying attention to do all the signs correctly, we obtain

$y = \frac{1}{2} x - 1$.

We are now in the initial format where $m = \frac{1}{2}$ and $q = - 1$.
So the slope is $\frac{1}{2}$ and the intercept is $- 1$.