# How do you find the slope and intercept of 6y+6 = 0?

Aug 2, 2018

The slope is $0$.

There is no $x$-intercept.

The $y$-intercept is at $\left(0 , - 1\right)$.

#### Explanation:

$6 y + 6 = 0$

First, make $y$ by itself. Subtract $\textcolor{b l u e}{6}$ from both sides:
$6 y + 6 \quad \textcolor{b l u e}{- \quad 6} = 0 \quad \textcolor{b l u e}{- \quad 6}$

$6 y = - 6$

Divide both sides by $\textcolor{b l u e}{6}$:
$\frac{6 y}{\textcolor{b l u e}{6}} = \frac{- 6}{\textcolor{b l u e}{6}}$

$y = - 1$

When the equation is $y$ equals to a number constant, that means it is a horizontal slope, or it has a slope of $0$.

There is no $x$-intercept since the equation never touches the $x$-axis. The $y$-intercept would be at $\left(0 , - 1\right)$, since whatever $x$-value you put into the equation does nothing. The equation is a constant, and it is always where $y = - 1$.

Hope this helps!