How do you find the slope and intercept of #8x -y=9#?

1 Answer
May 3, 2018

Answer:

Slope of the line = #8#

x-intercept = #-9/8#

y-intercept = #-9#

Explanation:

From linear equation of a line, #y=mx+c# or #y=mx+b#
Slope of a line is m and y-intercept is c (or b).
So first we have to make y the subject in #8x-y=9#
#8x-y=9#
#-y=9-8x#
Multiply by -1 both sides, we get:
#(-1).-y = (-1).9 - (-1)(8x)#
#y=-9 + 8x#
#y = 8x -9# ------> this is now same as #y=mx+c#

Hence slope is #8# and y-intercept is #-9#.

for x-intercept, put #y=0# and we get:
#0 = 8x - 9#
#9 = 8x#
#x = 9/8#
Hence, x-intercept is #9/8#