How do you find the slope and intercept of #x- y=2#?

Question

6536 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-02T07:56:57

#"slope "=1#

#"intercept "=-2#

rearrange to the form #y=mx+c#

#x-y=2#

#=>y=x-2#

#m=#gradient/slope

#:. "slope "=1#

#c="intercept"#

#"intercept "=-2#

as shown on the graph

graph{x-y=2 [-10, 10, -5, 5]}

Answer 2 · 2018-06-02T07:58:35

the slope is #1# and the intercepts are #y=-2# and #x=2#

Writing your equation in the form
#y=x-2#
we get the slope of #1#
and
#P_1(0;-2)#
and
#P_2(2;0)#