# How do you find the slope and intercept of #y= -2/5x + 20#?

##### 2 Answers

#### Explanation:

#"the equation of a line in "color(blue)"slope-intercept form"# is.

#•color(white)(x)y=mx+b#

#"where m is the slope and b the y-intercept"#

#y=-2/5x+20" is in this form"#

#"with slope "=-2/5" and y-intercept "=20#

Slope

#### Explanation:

The given equation is the standard slope-intercept form of a straight line equation,

where

#m =# slope#-># tangent of the angle made by the straight line intercepting one of the axes (#x# or#y# )#c =# the#y# -intercept, which remains constant.

Thus putting your equation in accordance with the standard equation, the slope is

graph{y = -2/5x + 20 [-80, 80, -40, 40]}

Since the slope is negative in magnitude, the tangent of the angle is greater than

Here the straight line cuts the positive