# How do you find the slope and intercept of y = 6x + 1?

Mar 25, 2018

m = $6$

x-intercept = $\left(- \frac{1}{6} , 0\right)$

y-intercept = $\left(0 , 1\right)$

#### Explanation:

$\textcolor{b l u e}{\text{Slope}}$ = $\textcolor{b l u e}{\frac{r i s e}{r u n}}$
Since 6 is essentially $\frac{6}{1}$ we know that the slope goes up 6 units

and right 1 unit on a graph.

Next, $\textcolor{b l u e}{\text{to find the y-intercept}}$ of y=6x+1, you substitute x as x=0."#

$y = 6 x + 1$

$y = 6 \left(0\right) + 1$

$y = 1$

$\therefore$ the y-intercept is 1 when x is 0 thus $\left(0 , 1\right)$

$\textcolor{b l u e}{\text{To find the x-intercept}}$ of y=6x+1, you let y=0.

$y = 6 x + 1$

$0 = 6 x + 1$

$0 - 1 = 6 x$

$- 1 = 6 x$

$x = - \frac{1}{6}$

$\therefore$ the x-intercept is -1/6 when y is 0 thus $\left(- \frac{1}{6} , 0\right)$

graph{6x+1 [-10, 10, -5, 5]}