How do you find the slope and intercept of #y=-x-7#?

2 Answers
Aug 3, 2018

Answer:

Slope: -1

x-intercept: (-7, 0)

y-intercept: (0, -7)

Explanation:

#y = -x - 7#

This equation is in slope-intercept form:
www.geogebra.org

Based on the image, we know that the slope is the value multiplied by #x#, so the slope is #-1#.

We know the #y#-intercept is #b#, or #-7#, so it is at #(0, -7)#.

To find the #x#-intercept, plug in #0# for #y# and solve for #x#:
#0 = -x - 7#

#7 = -x#

#x = -7#

The #x#-intercept is at #(-7, 0)#.'

Hope this helps!

Aug 4, 2018

Answer:

Slope #-1#, #y#-int #-7#, #x#-int #-7#

Explanation:

The good thing is that this equation is in slope-intercept form

#y=mx+b#, with slope #m# and a #y#-intercept of #b#.

By pattern matching, we see that our slope is #-1#, and our #y#-intercept is #-7#.

We can find our #x#-intercept by setting #y# equal to zero. We get

#-x-7=0=>-x=7=>x=-7#

Therefore, our slope is #-1#, our #y#-intercept is #-7#, and our #x#-intercept is #-7#.

Hope this helps!