# How do you find the slope and intercept to graph 7y+8x+6=16+8x?

Apr 9, 2016

slope = 0 , intercept $= \frac{10}{7}$

#### Explanation:

First , we require to find the equation of the line in the form
y = mx + c, where m represents the gradient (slope) and c , the y-intercept.

Rearrange 7y + 8x + 6 = 16 + 8x into this form.

hence : 7y = 16 + 8x - 8x - 6 = 10 → 7y = 10

divide both sides by 7.

$\frac{\cancel{7} y}{\cancel{7}} = \frac{10}{7} \Rightarrow y = \frac{10}{7} \text{ is the equation }$

This is a special case , of the equation of a line.

It passes through all points on the plane with a y-coord $= \frac{10}{7}$
It is therefore parallel to the x-axis and has a slope = 0

Here is the graph of y $= \frac{10}{7}$
graph{0x+10/7 [-10, 10, -5, 5]}