# How do you find the slope and y intercept for:  x +8y=0?

Nov 12, 2015

Slope: $\left(- \frac{1}{8}\right)$
y-intercept: $0$

#### Explanation:

Method 1
A linear equation in the form:
$\textcolor{w h i t e}{\text{XXX}} A x + B y = C$
the slope is $\left(- \frac{A}{B}\right)$
and
the y-intercept can be evaluated by setting $x$ to $0$ and solving for $y$

For the given equation
$\textcolor{w h i t e}{\text{XXX}} x + 8 y = 0$
the slope is $\left(- \frac{\left(1\right)}{8}\right) = - \frac{1}{8}$
and with $x = 0$
$\textcolor{w h i t e}{\text{XXX}} 0 + 8 y = 0 \Rightarrow y = 0$

Method 2
Convert the equation in its given form into slope-intercept form.

$x + 8 y = 0$

$\rightarrow 8 y = - x$

$\rightarrow y = - \frac{1}{8} x$

$\rightarrow y = \left(- \frac{1}{8}\right) x + 0$
$\textcolor{w h i t e}{\text{XXX}}$which is the slope-intercept form for a linear equation
with slope $\left(- \frac{1}{8}\right)$ and y-intercept $0$