How do you find the slope and y intercept for: # x +8y=0#?

1 Answer
Nov 12, 2015

Answer:

Slope: #(-1/8)#
y-intercept: #0#

Explanation:

Method 1
A linear equation in the form:
#color(white)("XXX")Ax+By=C#
the slope is #(-A/B)#
and
the y-intercept can be evaluated by setting #x# to #0# and solving for #y#

For the given equation
#color(white)("XXX")x+8y=0#
the slope is #(-((1))/8) = -1/8#
and with #x=0#
#color(white)("XXX")0+8y=0 rArr y=0#

Method 2
Convert the equation in its given form into slope-intercept form.

#x+8y=0#

#rarr 8y=-x#

#rarr y = -1/8x#

#rarr y = (-1/8)x + 0#
#color(white)("XXX")#which is the slope-intercept form for a linear equation
with slope #(-1/8)# and y-intercept #0#