# How do you find the slope-intercept form for the equation of the line which passes through the point (–1, –2) and is parallel to the line that has an equation of 6x + 2y = 4?

Apr 10, 2016

$3 x + y + 5 = 0$

#### Explanation:

When a line is parallel to say $a x + b y = c$, it is of the form $a x + b y = k$, where $k$ is some other number.

Hence a line parallel to $6 x + 2 y = 4$ will be of type $6 x + 2 y = k$,

As it passes through $\left(- 1 , - 2\right)$

$6 \cdot \left(- 1\right) + 2 \cdot \left(- 2\right) = k$

or $- 6 - 4 = k$ i.e. $k = - 10$

Hence equation of line $6 x + 2 y = - 10$ or $6 x + 2 y + 10 = 0$ or dividing by $2$ it becomes $3 x + y + 5 = 0$.