# How do you find the slope of a line parallel to Y-3=0?

Aug 2, 2017

See a solution process below:

#### Explanation:

We can rewrite this equation as:

$y - 3 + \textcolor{red}{3} = 0 + \textcolor{red}{3}$

$y - 0 = 3$

$y = 3$

This equation represents a horizontal line where for each and every value of $x$, $y$ is equal to $3$.

By definition, the slope of a horizontal line is $0$.

We can also show this by writing this equation in slope-intercept form. The slope-intercept form of a linear equation is: $y = \textcolor{red}{m} x + \textcolor{b l u e}{b}$

Where $\textcolor{red}{m}$ is the slope and $\textcolor{b l u e}{b}$ is the y-intercept value.

$y = \textcolor{red}{0} x + \textcolor{b l u e}{3}$

Therefore, the slope is: $\textcolor{red}{m = 0}$