How do you find the slope of the graph of $3 x + 5 y = 10$ $3x+5y=10$ ?

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Answer 1 · 2018-05-05T15:28:48

$- \frac{3}{5}$ $-3/5$ is the slope of the line.

Rearrange the equation into slope-intercept form to find the slope:

$y = m x + b$ $y = mx + b$

$m = slope$ $"m = slope"$
$b = y-intercept$ $"b = y-intercept"$

So rearrange the problem so that the $y$ $y$ is by itself on the left of the equal sign:

$3 x + 5 y = 10$ $3x +5y=10$

$5 y = - 3 x + 10$ $5y = -3x + 10$

$y = - \frac{3}{5} x + \frac{10}{5}$ $y = -3/5x + 10/5$

$y = - \frac{3}{5} x + 2$ $y = -3/5x + 2$

The slope is next to the $x$ $x$ , so it is called $m$ $m$ in the slope-intercept form:

$y = m x + b$ $y = color(blue)mx + b$

$y = - \frac{3}{5} x + 2$ $y = color(blue)(-3/5)x + 2$

$- \frac{3}{5}$ $-3/5$ is the slope of the line.

How do you find the slope of the graph of 3x+5y=103x+5y=103x+5y=10?