# How do you find the slope of the tangent line to the graph of the function f(x)=3-2x at (-1,5)?

Jul 14, 2017

$\text{slope } = - 2$

#### Explanation:

$\text{note that}$

$\text{slope (m) " =f'(x)" at x = a}$

$f \left(x\right) = 3 - 2 x \Rightarrow f ' \left(x\right) = - 2$

$\text{this means that the slope at any point on the line is - 2}$

$\text{of course "f(x)=3-2x" is a linear equation with m = -2}$