# How do you find the slope of the tangent line to the graph of the function f(x)=3/2x+1 at (-2,-2)?

$m = \frac{3}{2}$
$f \left(x\right) = \frac{3}{2} x + 1$ is a straight line, comparing with $y = m x + c$ we see $m = \frac{3}{2}$, so the gradient of the tangent line is $\frac{3}{2}$ everywhere.