Question

How do you find the slope of the tangent line to the graph of the function `f(x)=5-x^2` at (2,1)?

Answer 1

Please see the explanation for steps leading to the slope, `m = -4`

Explanation:

The first derivative is:

`f'(x) = -2x`

The slope, m, at x = 2 is:

`m = f'(2)`

`m = -2(2)`

`m = -4`