# How do you find the slope of the tangent line to the graph of the function f(x)=5-x^2 at (2,1)?

Nov 12, 2016

Please see the explanation for steps leading to the slope, $m = - 4$

#### Explanation:

The first derivative is:

$f ' \left(x\right) = - 2 x$

The slope, m, at x = 2 is:

$m = f ' \left(2\right)$

$m = - 2 \left(2\right)$

$m = - 4$